document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618289>Question 618289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i factor this equation 24m to the second power minus 105m minus 75? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388816 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=24m%5E2+-+105m+-+75 ALIGN=MIDDLE  ALT=\"24m%5E2+-+105m+-+75\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A%288m%5E2+-+35m+-+25%29 ALIGN=MIDDLE  ALT=\"3%2A%288m%5E2+-+35m+-+25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > 8 has the factors 1,8  and 4,2. 25 has factors 1,25 and 5,5. fond the combination that gives you a -35 for the middle term. (8*(-5) + 1*5)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A%288m+%2B+5%29%28m+-+5%29 ALIGN=MIDDLE  ALT=\"3%2A%288m+%2B+5%29%28m+-+5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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