document.write( "Question 618292: shila is 15 years older than her brother sanjay. ten years from now shila will be twice as sanjay. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #388808 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Shila = h \n" ); document.write( "Present age of Sanjay = s\r \n" ); document.write( "\n" ); document.write( "Shila is 15 years older than Sanjay \n" ); document.write( "h=s+15............(1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ten years after \n" ); document.write( "Shila will be = h+10 \n" ); document.write( "Sanjay will be = s+10\r \n" ); document.write( "\n" ); document.write( "Then \n" ); document.write( "Shila will be twice as Sanjay\r \n" ); document.write( "\n" ); document.write( "(h+10)=2(s+10) \n" ); document.write( "h+10=2s+20 \n" ); document.write( "h=2s+20-10 \n" ); document.write( "h=2s+10...................(2)\r \n" ); document.write( "\n" ); document.write( "Substitute the value of h from (1) to (2) \n" ); document.write( "s+15=2s+10 \n" ); document.write( "s-2s=10-15 \n" ); document.write( "-s=-5 \n" ); document.write( "Cancel out (-) \n" ); document.write( "s=5 \n" ); document.write( "Put the value of s in (1) \n" ); document.write( "h=s+15...........(1) \n" ); document.write( "h=5+15 \n" ); document.write( "h=20\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Shila = h = 20 \n" ); document.write( "Present age of Sanjay = s = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |