document.write( "Question 618259: a boat traveled 88 miles downstream and back. the trip downstream took 4 hours. the trip back took 44 hours. what is the speed of the boat in still water? what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #388807 by lwsshak3(11628)\"\" \"About 
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a boat traveled 88 miles downstream and back. the trip downstream took 4 hours. the trip back took 44 hours. what is the speed of the boat in still water? what is the speed of the current?
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\n" ); document.write( "let x=speed of boat in still water
\n" ); document.write( "let c=speed of current
\n" ); document.write( "x+c=net speed of boat downstream
\n" ); document.write( "x+c=net speed of boat upstream
\n" ); document.write( "travel time=distance/speed
\n" ); document.write( "..
\n" ); document.write( "88/(x+c)=4
\n" ); document.write( "88/(x-c)=44
\n" ); document.write( "..
\n" ); document.write( "4x+4c=88
\n" ); document.write( "44x-44c=88
\n" ); document.write( "..
\n" ); document.write( "multiply first equation by 11
\n" ); document.write( "44x+44c=968
\n" ); document.write( "44x-44c=88
\n" ); document.write( "add
\n" ); document.write( "88x=1056
\n" ); document.write( "x=12
\n" ); document.write( "4c=88-4x=88-48=40
\n" ); document.write( "c=10
\n" ); document.write( "ans:
\n" ); document.write( "speed of boat in still water=12 mph
\n" ); document.write( "speed of current=10 mph
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