document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618258>Question 618258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2log[4](3x)+log[4](11)=14<BR>\n" );
document.write( "Solve. I don't know how to. The answer I could come up with is <BR>\n" );
document.write( "2log[4](3)+2log[4](x)+log[4](11)=14<BR>\n" );
document.write( "But I don't think that's right. Is it? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388806 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2log[4](3x)+log[4](11)=14<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log4[(3x)^2*11]=14<BR>\n" );
document.write( "convert to exponential form: base(4) raised to log of number(14)=number[(3x)^2*11]<BR>\n" );
document.write( "4^14=[(3x)^2*11]=99x^2<BR>\n" );
document.write( "x^2=4^14/99<BR>\n" );
document.write( "x=&#8730;(4^14/99)&#8776;2711469.25<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );