document.write( "Question 618297: What is log(base3)8+log(base3)(7-2x)=2 \n" ); document.write( "
Algebra.Com's Answer #388805 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log(base3)8+log(base3)(7-2x)=2
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\n" ); document.write( "\"log%283%2C8%29+%2B+log%283%2C7-2x%29+=+2\"
\n" ); document.write( "\"log%283%2C8%287-2x%29%29+=+2\"
\n" ); document.write( "\"8%287-2x%29+=+8%5E2\"
\n" ); document.write( "\"56-16x+=+64+\"
\n" ); document.write( "\"-16x+=+8+\"
\n" ); document.write( "\"x+=+8%2F%28-16%29+\"
\n" ); document.write( "\"x+=+1%2F%28-2%29+\"
\n" ); document.write( "\"x+=+-1%2F2+\"
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