document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618296>Question 618296</A>: <I><SPAN STYLE=\"word-break: break-all;\">  What is log(base3)8+log(base3)(7-2x)=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388799 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is log(base3)8+log(base3)(7-2x)=2<BR>\n" );
document.write( "log3(8)+log3(7-2x)=2<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log3[8*(7-2x)]=2<BR>\n" );
document.write( "convert to exponential form:<BR>\n" );
document.write( "3^2=8(7-2x)<BR>\n" );
document.write( "9=56-16x<BR>\n" );
document.write( "16x=47<BR>\n" );
document.write( "x=47/16 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );