document.write( "Question 618287: a two digit number has a value two more than six times the sum of its digits. the tens digit is one more than the units digit. find the number \n" ); document.write( "
Algebra.Com's Answer #388785 by dragonwalker(73)![]() ![]() ![]() You can put this solution on YOUR website! Let us say that the unit digit is 'u' and the tens digit is 't'\r \n" ); document.write( "\n" ); document.write( "The number can then be written as 10t + u\r \n" ); document.write( "\n" ); document.write( "We know that 10t + u - 2 = 6t + 6u\r \n" ); document.write( "\n" ); document.write( "also:\r \n" ); document.write( "\n" ); document.write( "t = u + 1\r \n" ); document.write( "\n" ); document.write( "substitute t from second equation into the first full equation:\r \n" ); document.write( "\n" ); document.write( "10(u+1) + u - 2 = 6(u+1) + 6u \n" ); document.write( "10u + 10 + u - 2 = 6u + 6 + 6u\r \n" ); document.write( "\n" ); document.write( "rearrange so all 'u's on left and numbers on right. Remember to change the sign if you change the side that a value is on:\r \n" ); document.write( "\n" ); document.write( "10u + u - 6u - 6u = 6 + 2 - 10\r \n" ); document.write( "\n" ); document.write( "-u = -2\r \n" ); document.write( "\n" ); document.write( "so:\r \n" ); document.write( "\n" ); document.write( "u = 2\r \n" ); document.write( "\n" ); document.write( "so if u=2 then t must be equal to 3 (u+1=t)\r \n" ); document.write( "\n" ); document.write( "the number is 32\r \n" ); document.write( "\n" ); document.write( "to check:\r \n" ); document.write( "\n" ); document.write( "Sum of its digits times six is: 2+3 = 5 times by 6 = 30.\r \n" ); document.write( "\n" ); document.write( "the number is 32 which is indeed two more than 30 \n" ); document.write( " |