document.write( "Question 618230: How would i work the following problem on my T1 84?\r
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\n" ); document.write( "\n" ); document.write( "The line that is parallel to the line 2x + 3y=4 and passes through point (1,2).
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Algebra.Com's Answer #388777 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The TI-84 won't help you until you get the equation in\r\n" );
document.write( "the form y = mx + b, and you have to find the equation \r\n" );
document.write( "all by yourself.\r\n" );
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document.write( "Get this in the form y = mx + b\r\n" );
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document.write( "2x + 3y = 4\r\n" );
document.write( "     3y = -2x + 4\r\n" );
document.write( "     \"3%2F3\"y = \"%28-2%29%2F3\"x + \"4%2F3\"\r\n" );
document.write( "      y = \"-2%2F3\"x + \"4%2F3\"\r\n" );
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document.write( "Compare to \r\n" );
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document.write( "      y = mx + b\r\n" );
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document.write( "And you see that m = \"-2%2F3\"\r\n" );
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document.write( "That's the slope of the given line and also the\r\n" );
document.write( "slope of the desired line.  Next we use the\r\n" );
document.write( "point-slope form of the equation of a line, \r\n" );
document.write( "which is:\r\n" );
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document.write( "y - y1 = m(x - x1)\r\n" );
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document.write( "Where m = \"-2%2F3\" and (x1, y1) = (1,2)\r\n" );
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document.write( "y - 2 = \"-2%2F3\"(x - 1)\r\n" );
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document.write( "y - 2 = \"-2%2F3\"x + \"2%2F3\"\r\n" );
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document.write( "    y = \"-2%2F3\"x + \"2%2F3\" + 2\r\n" );
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document.write( "    y = \"-2%2F3\"x + \"2%2F3\" + \"6%2F3\"\r\n" );
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document.write( "    y = \"-2%2F3\"x + \"8%2F3\" \r\n" );
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document.write( "Now you can get the calculator to graph it.\r\n" );
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document.write( "Press Y=  and after \Y1= type\r\n" );
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document.write( "     -2/3X+8/3  so that it looks like this:\r\n" );
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document.write( "\Y1=-2/3X+8/3\r\n" );
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document.write( "Press ZOOM\r\n" );
document.write( "Press 6\r\n" );
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document.write( "Then you see this:\r\n" );
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document.write( "\"graph%28600%2C18600%2F47%2C-10%2C10%2C-10%2C10%2C%28-2%2F3%29x%2B8%2F3%29\"\r\n" );
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document.write( "Edwin
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