document.write( "Question 57158This question is from textbook
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document.write( ": Last Monday at 7:30 a.m., an airline flew 89 passengers on a commuter flight from Boston to New York. Some of the passengers paid $120 for their tickets and the rest paid $230 for their tickets. The total cost of all of the tickets was $14,200. How many passengers bought $120 tickets? How many bought $230 tickets? \n" );
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Algebra.Com's Answer #38877 by rcmcc(152)![]() ![]() You can put this solution on YOUR website! To solve this question you must change the word problem to a linear equation.\r \n" ); document.write( "\n" ); document.write( "This can be done by making the passengers that paid $120 for their ticket (X) and the passenger that paid $230 for their ticket (Y)\r \n" ); document.write( "\n" ); document.write( "The total amount of passengers is;\r \n" ); document.write( "\n" ); document.write( "X+Y=89\r \n" ); document.write( "\n" ); document.write( "and the ticket cost per passenger can be represented by;\r \n" ); document.write( "\n" ); document.write( "120X+230Y=14200\r \n" ); document.write( "\n" ); document.write( "by multiplying the first equation by 120, you can solve the system for y. This is shown below.\r \n" ); document.write( "\n" ); document.write( "(X+Y=89)x120 \n" ); document.write( "120X+120Y=10680\r \n" ); document.write( "\n" ); document.write( "isolate Y from the 2 equations;\r \n" ); document.write( "\n" ); document.write( "120X+120Y=10680 \n" ); document.write( "120X+230Y=14200 \n" ); document.write( "-110Y=-3520 \n" ); document.write( "Y=32\r \n" ); document.write( "\n" ); document.write( "Substitute Y into the first equation to find X\r \n" ); document.write( "\n" ); document.write( "X+Y=89 \n" ); document.write( "X+32=89 \n" ); document.write( "X=57\r \n" ); document.write( "\n" ); document.write( "So 57 passengers paid $120 and 32 paid $230 \n" ); document.write( " |