document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618217>Question 618217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car takes 10s to go from v=0 m/s to v= 25 m/s at constant acceleration. If you wish to find the distance traveled using the equation d=1/2atsquared what value should you use for a?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388768 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388768\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A car takes 10s to go from v=0 m/s to v= 25 m/s at constant acceleration. If you wish to find the distance traveled using the equation d=1/2atsquared what value should you use for a? <BR>\n" );
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document.write( "a = v/t = 25/10<BR>\n" );
document.write( "a = 2.5 m/sec/sec<BR>\n" );
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document.write( "s = at^2/2 = 2.5*10^2/2<BR>\n" );
document.write( "s = 125 meters\r<BR>\n" );
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