document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618152>Question 618152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use log4^3=0.7925 and log4^4=1 to approximate the value of the expression log4^384<BR>\n" );
document.write( "Show all work please and explain if you could  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388730 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use log4^3=0.7925 and log4^4=1 to approximate the value of the expression log4^384<BR>\n" );
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document.write( "You mean log base 4, not exponents.<BR>\n" );
document.write( "^ is exponentiation.<BR>\n" );
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document.write( "384 = 3*128 = 3*4^3*4^(1/2)<BR>\n" );
document.write( "log(384) = log(3) + 3*log(4) + (1/2)*log(4)  with any consistent base<BR>\n" );
document.write( "= 0.7925 + 3 + 0.5<BR>\n" );
document.write( "= 4.2925<BR>\n" );
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