document.write( "Question 57164This question is from textbook
\n" ); document.write( ": here's the sequence:
\n" ); document.write( "1, 1/4, 1/9 ,1/16 or 1, .25, 1.111111repeating, .0625
\n" ); document.write( "What is the pattern?? and if you figure out the pattern, i'll find out on my own the next two numbers.
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Algebra.Com's Answer #38873 by rcmcc(152)\"\" \"About 
You can put this solution on YOUR website!
The pattern of your sequence is an expanded geometric sequence. It is calculated by taking the inverse of the square of the term. Or by the formula below.\r
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\n" ); document.write( "\n" ); document.write( "T= 1/(tn^2)\r
\n" ); document.write( "\n" ); document.write( "so, your sequence is:\r
\n" ); document.write( "\n" ); document.write( "1=1/(1^2)
\n" ); document.write( "(1/4)=1/(2^2)
\n" ); document.write( "(1/9)=1/(3^2)
\n" ); document.write( "(1/16)=1/(4^2)\r
\n" ); document.write( "\n" ); document.write( "and the next 2 numbers can be solved by\r
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\n" ); document.write( "\n" ); document.write( "T5=1/(5^2)
\n" ); document.write( "T5=1/25\r
\n" ); document.write( "\n" ); document.write( "T6=1/(6^2)
\n" ); document.write( "T6=1/36
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