document.write( "Question 618104: A line through(2 , 1)meets the curve x squared - 2x - y=3 at A(-2 , 5) and at B.Find the coordinates of B. \n" ); document.write( "

Algebra.Com's Answer #388712 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
\n" );
document.write( "Hi, 
\n" );
document.write( "A line through(2 , 1)meets the curve x^2- 2x - y=3 at A(-2 , 5) and at B
\n" );
document.write( "the line passing through (2,1) and (-2,5)
\n" );
document.write( "(2,1) and 
\n" );
document.write( "(-2,5)  m = -4/4 = -1
\n" );
document.write( " y = -x + b
\n" );
document.write( " 1 = -2 + b     ||Using PT(2,1) to solve for b
\n" );
document.write( "  3 = b
\n" );
document.write( "  = -x + 3   AND  x^2- 2x - y=3 or  = x^2- 2x - 3
\n" );
document.write( "  x^2-2x-3 = -x + 3
\n" );
document.write( "  x^2-x - 6 = 0
\n" );
document.write( " (x-3)(x+2) = 0
\n" );
document.write( "  (x+2) = 0  We have A(-2 , 5)
\n" );
document.write( " (x-3) = 0    B(3,0)      |||  = -x + 3 
\n" );
document.write( "
\n" );
document.write( " \n" );
document.write( "

\n" );