document.write( "Question 618107: How do you write the equation of the indicated conic in standard form?\r
\n" ); document.write( "\n" ); document.write( "Ellipse: Vertices:(-4,6),(8,6) Co-vertices:(2,8),(2,4)
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Algebra.Com's Answer #388704 by lwsshak3(11628)\"\" \"About 
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How do you write the equation of the indicated conic in standard form?
\n" ); document.write( "Ellipse: Vertices:(-4,6),(8,6) Co-vertices:(2,8),(2,4)
\n" ); document.write( "**
\n" ); document.write( "This is an ellipse with horizontal major axis:
\n" ); document.write( "Its equation: (x-h)^2/a^2+(y-k)^2/b^2=1, a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "y-coordinate of center=6
\n" ); document.write( "x-coordinate of center=2 (8-4)/2=2 (midpoint formula)
\n" ); document.write( "center: (2,6)
\n" ); document.write( "length of horizontal major axis=12 (-4 to 8)=2a
\n" ); document.write( "a=6
\n" ); document.write( "a^2=36
\n" ); document.write( "..
\n" ); document.write( "length of co-vertices of minor axis=4 (4 to 8)=2b
\n" ); document.write( "b=2
\n" ); document.write( "b^2=4
\n" ); document.write( "..
\n" ); document.write( "Equation:
\n" ); document.write( "(x-2)^2/36+(y-6)^2/4=1
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