document.write( "Question 617926: log[6](x-2)+log[6](x+3)=1 \n" ); document.write( "
Algebra.Com's Answer #388669 by nerdybill(7384)\"\" \"About 
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log[6](x-2)+log[6](x+3)=1
\n" ); document.write( "log[6][(x-2)(x+3)]=1
\n" ); document.write( "(x-2)(x+3) = 6^1
\n" ); document.write( "x^2+x-6 = 6
\n" ); document.write( "x^2+x-12 = 0
\n" ); document.write( "(x+4)(x-3) = 0
\n" ); document.write( "x = {-4, 3}
\n" ); document.write( "Throw out the negative solution (extraneous) leaving:
\n" ); document.write( "x = 3\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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