document.write( "Question 617903: can i please have help in solving this linear function. f(x) has slope-2/3 and contains the point f(-3)=0. What is f(0)? \n" ); document.write( "
Algebra.Com's Answer #388623 by nerdybill(7384)\"\" \"About 
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f(x) has slope-2/3 and contains the point f(-3)=0. What is f(0)?
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\n" ); document.write( "slope intercept form of a line:
\n" ); document.write( "y = mx + b
\n" ); document.write( "to find 'b', plug in the given info from the problem:
\n" ); document.write( "m is -2/3
\n" ); document.write( "y is 0
\n" ); document.write( "x is -3
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\n" ); document.write( "y = mx + b
\n" ); document.write( "0 = (-2/3)(-3) + b
\n" ); document.write( "0 = 2 + b
\n" ); document.write( "-2 = b
\n" ); document.write( ".
\n" ); document.write( "So, our equation of the line is:
\n" ); document.write( "f(x) = (-2/3)x - 2
\n" ); document.write( ".
\n" ); document.write( "To find f(0), plug it in:
\n" ); document.write( "f(x) = (-2/3)x - 2
\n" ); document.write( "f(0) = (-2/3)0 - 2
\n" ); document.write( "f(0) = -2 (notice, this is the same as 'b' (y-intercept) found earlier)\r
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