document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57144>Question 57144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/5m+a=b, for m\r<BR>\n" );
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document.write( "please help, i have no i dea how 2 do these with fractions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38861 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/5m+a=b<BR>\n" );
document.write( "3/5m+a-a=b-a<BR>\n" );
document.write( "3/5m=b-a<BR>\n" );
document.write( "(5/3)3/5m=5/3(b-a)<BR>\n" );
document.write( "m=5/3(b-a)<BR>\n" );
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document.write( "Check by plugging [m= 5/3(b-a) ] back into the original equation.<BR>\n" );
document.write( "3/5m+a=b<BR>\n" );
document.write( "3/5[5/3(b-a)]+a=b<BR>\n" );
document.write( "b-a+a=b<BR>\n" );
document.write( "b=b [Checks out] </SPAN>\n" );
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