document.write( "Question 617858: please help me solve this problem: A chemist has 6 liter of a 50% acid solution. How much water must be added to obtain a 20% acid solution.- i tryed with these two problems: 6+.50=y and 6(.50)+y= .20x but i don't get the right answer please help me try to figure out what i did wrong \n" ); document.write( "

Algebra.Com's Answer #388590 by stanbon(75887) $\"\"$ $\"About$

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A chemist has 6 liter of a 50% acid solution. How much water must be added to obtain a 20% acid solution.
\n" ); document.write( "Equation:
\n" ); document.write( "water + water = water
\n" ); document.write( "0.50*6 + x = 0.80(6+x)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "50*6 + 100x = 80*6 + 80x
\n" ); document.write( "20x = 30*6
\n" ); document.write( "x = (3/2)6
\n" ); document.write( "x = 9 liters (amt. of water to be added)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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