document.write( "Question 617814:
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document.write( "What quantity of 80 percent acid solution must be mixed with a 25 percent solution to produce 1056 ml of a 50 percent solution?
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Algebra.Com's Answer #388575 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "What quantity of 80 percent acid solution must be mixed with a 25 percent solution to produce 1056 ml of a 50 percent solution? \n" ); document.write( "------ \n" ); document.write( "Do it like this:\r \n" ); document.write( "\n" ); document.write( "if a 14% acid solution is mixed with a 19% acid solution to produce 45 gallons of a 15% acid solution how much (in gallons) of each solution should be used? \n" ); document.write( "-------------- \n" ); document.write( "f = 14% \n" ); document.write( "n = 19% \n" ); document.write( "---- \n" ); document.write( "f + n = 45 (total gallons) \n" ); document.write( "14f + 19n = 15*45 (total acid) \n" ); document.write( "----- \n" ); document.write( "n = 45 - f \n" ); document.write( "Sub for n \n" ); document.write( "14f + 19*(45-f) = 675 \n" ); document.write( "14f + 855 - 19f = 675 \n" ); document.write( "-5f = -180 \n" ); document.write( "f = 36 gallons of 14% \n" ); document.write( "n = 9 gallons of 19% \n" ); document.write( " |