document.write( "Question 57129: please put in simple terms that i can understand\r
\n" ); document.write( "\n" ); document.write( "v=r+at, for the a
\n" ); document.write( "

Algebra.Com's Answer #38857 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
v = r + at, for the a
\n" ); document.write( ":
\n" ); document.write( "The idea is to perform various math opertations on the equation to get 'a' on one side of the equation by itself. You can do all 4 math operations +,-,*,/, as long as you do the same to both sides.
\n" ); document.write( ":
\n" ); document.write( "v = r + at
\n" ); document.write( "Subtract r from both sides:
\n" ); document.write( "v - r = r - r + at
\n" ); document.write( "v - r = at
\n" ); document.write( ":
\n" ); document.write( "Since 'at' means a*t we have to divide 'at' by 't' to get 1a which is just 'a'
\n" ); document.write( "Divide both sides by t:
\n" ); document.write( "\"%28v-r%29%2Ft\" = \"%28at%29%2Ft\"
\n" ); document.write( "The t's cancel so you have:
\n" ); document.write( "\"%28v-r%29%2Ft\" = a
\n" ); document.write( "Normally this would be written:
\n" ); document.write( "a = \"%28%28v-r%29%29%2Ft\"
\n" ); document.write( ":
\n" ); document.write( "Did this make sense to you?
\n" ); document.write( "
\n" ); document.write( "
\n" );