document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=617776>Question 617776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 12 liters of a 36% acid solution. How many liters of 18% acid should be combined with a 45% acid solution to obtain the proper mixture?\r<BR>\n" );
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document.write( "My teacher didn't teach us this at all. Please, provide an explanation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388556 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation(s) are set up based on the \"active\" ingredient -- in this case, the acid\r<BR>\n" );
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document.write( "the final product is 12L of 36% acid<BR>\n" );
document.write( "___ to get that, you mix some amount of 18% acid; with -- 12L minus that amount -- of 45% acid\r<BR>\n" );
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document.write( "(x)(18%) + (12 - x)(45%) = (12)(36%) ___ multiplying by 100 to clear the percents is usually a good idea\r<BR>\n" );
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document.write( "18x + (12 * 45) - 45x = (12 * 36)\r<BR>\n" );
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document.write( "(12 * 45) - (12 * 36) = 45x - 18x\r<BR>\n" );
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document.write( "12 * 9 = 27x ___ 4 = x </SPAN>\n" );
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