document.write( "Question 617684: Suppose two sides of a square are given as x + 3 and 12 - x. What is its area? \n" ); document.write( "
Algebra.Com's Answer #388483 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! If this is a square, then it has equal sides. So x+3 = 12-x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+3 = 12-x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+x = 12-3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x = 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 9/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 4.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So each side is 4.5 + 3 = 7.5 units.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the area is 7.5^2 = 56.25 square units.\r \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "If this is really a rectangle, then the area is simply \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = (x+3)(12-x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = 12x - x^2 + 36 - 3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = -x^2 + 9x + 36 \n" ); document.write( " |