document.write( "Question 617682: (x + 2)^2 = 121 \n" ); document.write( "

Algebra.Com's Answer #388481 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"%28x%2B2%29%5E2=121\"$ Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%2B2=%22%22%2B-sqrt%28121%29\"$ Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%2B2=sqrt%28121%29\"$ or $\"x%2B2=-sqrt%28121%29\"$ Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( " $\"x%2B2=11\"$ or $\"x%2B2=-11\"$ Take the square root of $\"121\"$ to get $\"11\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"x=-2%2B11\"$ or $\"x=-2-11\"$ Subtract $\"2\"$ from both sides.\r
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\n" ); document.write( "\n" ); document.write( " $\"x=9\"$ or $\"x=-13\"$ Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are $\"x=9\"$ or $\"x=-13\"$ .
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