document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=617594>Question 617594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> over a period of 3 and 1/2 years 11/20inch of tire wear off.what is the average wear per year </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388417 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> over a period of 3 and 1/2 years 11/20inch of tire wear off.what is the average wear per year<BR>\n" );
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document.write( "(11/20)/3.5 = 0.55/3.5<BR>\n" );
document.write( "=~ 0.15714 in/yr<BR>\n" );
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