document.write( "Question 56993: this is a story problem. \"A rectangle whose perimeter is 192 is 3 times as long as it is wide. Find the dimensions and area.\" Can you please help me.
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Algebra.Com's Answer #38841 by rcmcc(152)\"\" \"About 
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You can solve this question by solving for X.
\n" ); document.write( "Let X be the width of the rectangle.
\n" ); document.write( "Since the length is 3 times greater than the width it can be stated as 3X
\n" ); document.write( "Because we are calculating perimeter all the values must be multiplied by 2, as there are two identical sides.
\n" ); document.write( "Now we can form a simple equation.
\n" ); document.write( "(2)3X+(2)X=192
\n" ); document.write( "Simplify the equation
\n" ); document.write( "6X+2X=192
\n" ); document.write( "8X=192
\n" ); document.write( "divide 8 out to isolate x
\n" ); document.write( "X=24
\n" ); document.write( "Hence the width is 24 and the length is 72
\n" ); document.write( "The area is LxW
\n" ); document.write( "24X72=1728
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