document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=617546>Question 617546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a diagonal of a rectangle is 10cm. The diagonal is inclined at an angle &#952;° to a side of the rectangle. Show that the perimeter,P cm, of the rectangle is given by P=20&#8730;2 sin (&#952;+45)° </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388395 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2x 10 sin y + 2x 10 cos y<BR>\n" );
document.write( "P = 20 (sin y + cos y)<BR>\n" );
document.write( "Convert to R sin (y + a) format<BR>\n" );
document.write( "R = 20 sqrt( 1 + 1)= 20 sqrt 2<BR>\n" );
document.write( "tan a = 1/1 =1 a = 45<BR>\n" );
document.write( "So P = 2- sqrt 2 ( sin (y - 45)) </SPAN>\n" );
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