document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57012>Question 57012</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me on the following problem: \"A rectangle whose perimeter is 200 is 4 times as long as it is wide. Find the dimensions and area.\" CAn you please help me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38838 by </B><A HREF=/tutors/aboutme.mpl?userid=rcmcc><B>rcmcc(152)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rcmcc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rcmcc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can solve this question by solving for X.\r<BR>\n" );
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document.write( "Let X be the width of the rectangle.\r<BR>\n" );
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document.write( "Since the length is 4 times greater than the width it can be stated as 4X\r<BR>\n" );
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document.write( "Because we are calculating perimeter all the values must be multiplied by 2, as there are two identical sides. \r<BR>\n" );
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document.write( "Now we can form a simple equation.\r<BR>\n" );
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document.write( "(2)4X+(2)X=200\r<BR>\n" );
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document.write( "Simplify the equation\r<BR>\n" );
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document.write( "8X+2X=200\r<BR>\n" );
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document.write( "10X=200\r<BR>\n" );
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document.write( "divide 10 out to isolate x\r<BR>\n" );
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document.write( "X=20\r<BR>\n" );
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document.write( "Hence the width is 20 and the length is 80\r<BR>\n" );
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document.write( "The area is LxW\r<BR>\n" );
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document.write( "20X80=1600 </SPAN>\n" );
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