document.write( "Question 617499: Two joggers set out at the same time from their homes 30 miles apart. They agree to meet at a point somewhere in between in two and a half hours. If the rate of one is 2 mph faster than the rate of the other, find the rate of each \n" ); document.write( "
Algebra.Com's Answer #388365 by ankor@dixie-net.com(22740)\"\" \"About 
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Two joggers set out at the same time from their homes 30 miles apart.
\n" ); document.write( " They agree to meet at a point somewhere in between in two and a half hours.
\n" ); document.write( " If the rate of one is 2 mph faster than the rate of the other, find the rate of each
\n" ); document.write( ":
\n" ); document.write( "let r = rate of the slower jogger
\n" ); document.write( "then
\n" ); document.write( "(r+2) = rate of the faster
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, dist = time * rate
\n" ); document.write( "2.5r + 2.5(r+2) = 30
\n" ); document.write( "2.5r + 2.5r + 5 = 30
\n" ); document.write( "5r = 30 - 5
\n" ); document.write( "5r = 25
\n" ); document.write( "r = 25/5
\n" ); document.write( "r = 5 mph is the slower jogger
\n" ); document.write( "and obviously
\n" ); document.write( "7 mph is the faster jogger
\n" ); document.write( ":
\n" ); document.write( ":
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\n" ); document.write( "Check the total distance, to confirm our solutions
\n" ); document.write( "2.5(5) + 2.5(7) =
\n" ); document.write( "12.5 + 17.5 = 30 \n" ); document.write( "
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