document.write( "Question 617512: (5y+3)^2+144=0 \n" ); document.write( "
Algebra.Com's Answer #388364 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"%285y%2B3%29%5E2%2B144=0\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285y%2B3%29%5E2=0-144\"Subtract \"144\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285y%2B3%29%5E2=-144\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5y%2B3=%22%22%2B-sqrt%28-144%29\" Take the square root of both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5y%2B3=sqrt%28-144%29\" or \"5y%2B3=-sqrt%28-144%29\" Break up the \"plus/minus\" to form two equations.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5y%2B3=12i\" or \"5y%2B3=-12%2Ai\" Simplify \"sqrt%28-144%29\" to get \"12i\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5y=-3%2B12i\" or \"5y=-3-12%2Ai\" Subtract \"3\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28-3%2B12i%29%2F5\" or \"y=%28-3-12i%29%2F5\" Divide both sides by 5
\n" ); document.write( "
\n" );