document.write( "Question 617401: In a bag are 4 yellow and 8 blue marbles. 3 are selected at random without replacement. What is the probability that all 3 are yellow or all 3 are blue? \n" ); document.write( "
Algebra.Com's Answer #388308 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! P(3 yellow) = (4/12)*(3/11)*(2/10) = 24/1320 = 1/55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(3 blue) = (8/12)*(7/11)*(6/10) = 336/1320 = 14/55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------\r \n" ); document.write( "\n" ); document.write( "P(3 Yellow OR 3 Blue) = P(3 yellow) + P(3 blue)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(3 Yellow OR 3 Blue) = 1/55 + 14/55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(3 Yellow OR 3 Blue) = 15/55\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(3 Yellow OR 3 Blue) = 3/11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: we can simply add the probabilities because the two events are mutually exclusive. \n" ); document.write( " \n" ); document.write( " |