document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=617384>Question 617384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We are supposed to solve the equation 4^2x-1=32^x+2.\r<BR>\n" );
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document.write( "So its supposed to be 4 to the 2x-1 power equals 32 to the x+2 power. I'm just having a hard time trying to figure this out. my mind does not think in logarithmic and exponential terms. Any help is greatly appreciated. Thank you for your time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388304 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Notice how 4 and 32 are powers of 2. So rewrite them as such and simplify...\r<BR>\n" );
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document.write( "4^(2x-1) = 32^(x+2)\r<BR>\n" );
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document.write( "(2^2)^(2x-1) = (2^5)^(x+2)\r<BR>\n" );
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document.write( "2^(2(2x-1)) = 2^(5(x+2))\r<BR>\n" );
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document.write( "Since the bases are equal (to 2), the exponents must be equal. So....\r<BR>\n" );
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document.write( "2(2x-1) = 5(x+2)\r<BR>\n" );
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document.write( "4x-2 = 5x+10\r<BR>\n" );
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document.write( "4x-5x = 10+2\r<BR>\n" );
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document.write( "-x = 12\r<BR>\n" );
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document.write( "x = -12\r<BR>\n" );
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document.write( "So the solution is <font color=\"red\">x = -12</font> </SPAN>\n" );
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