document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=617338>Question 617338</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem: 1/2 + (2/3 + 3/4) - (4/5 * 5/6)=?\r<BR>\n" );
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document.write( "This is as far as I got:\r<BR>\n" );
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document.write( "2/3= (2/3)(4/4)= 8/12<BR>\n" );
document.write( "3/4= (3/4)(3/3)= 9/12<BR>\n" );
document.write( "?= 17/12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388271 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Good, so 2/3 + 3/4 = 17/12 (the terms that change are in <font color=\"blue\">blue</font> and change to what's shown in <font color=\"green\">green</font>)\r<BR>\n" );
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document.write( "1/2 + <font color=\"blue\">(2/3 + 3/4)</font> - (4/5 * 5/6)\r<BR>\n" );
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document.write( "1/2 + <font color=\"green\">17/12</font> - (4/5 * 5/6)\r<BR>\n" );
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document.write( "Now keep going...\r<BR>\n" );
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document.write( "1/2 + 17/12 - 20/30\r<BR>\n" );
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document.write( "1/2 + 17/12 - 2/3\r<BR>\n" );
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document.write( "6/12 + 17/12 - 8/12\r<BR>\n" );
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document.write( "(6+17-8)/12\r<BR>\n" );
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document.write( "15/12\r<BR>\n" );
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document.write( "5/4\r<BR>\n" );
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document.write( "So 1/2 + (2/3 + 3/4) - (4/5 * 5/6) = <font color=\"red\">5/4</font> </SPAN>\n" );
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