document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=617266>Question 617266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Looking for someone to help on this. I tried it but am hoping to cross check it to see if I am doing it right. Thanks for any help.\r<BR>\n" );
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document.write( "12x + 7 - 3x = 56x + 9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388244 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12x + 7 - 3x = 56x + 9<BR>\n" );
document.write( "combining x's on the left side:<BR>\n" );
document.write( "9x + 7 = 56x + 9<BR>\n" );
document.write( "subtracting 9x from both sides:<BR>\n" );
document.write( "7 = 47x + 9<BR>\n" );
document.write( "subtracting 9 from both sides:<BR>\n" );
document.write( "-2 = 47x<BR>\n" );
document.write( "dividing both sides by 47<BR>\n" );
document.write( "-2/47 = x<BR>\n" );
document.write( "(or, approximately -0.04255) </SPAN>\n" );
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