document.write( "Question 617006: given that a rarabola has a directrix of y=-3.25 and focus (0,-2.75) find the vertex
\n" ); document.write( "please show step by step
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Algebra.Com's Answer #388232 by lwsshak3(11628) $\"\"$ $\"About$

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given that a parabola has a directrix of y=-3.25 and focus (0,2.75),...find the vertex
\n" ); document.write( "then write the equetion of the parabola and graph the parabola
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\n" ); document.write( "This is a parabola that opens upwards:
\n" ); document.write( "Its standard form of equation: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex, A=multiplier which affects width or steepness of the curve.
\n" ); document.write( "axis of symmetry: y-axis or x=0
\n" ); document.write( "x-coordinate of vertex=0
\n" ); document.write( "y-coordinate of vertex=3 (halfway between focus and directrix on the axis of symmetry)(2.75+3.25)/2=3
\n" ); document.write( "vertex: (0,3)
\n" ); document.write( "p=.25 (distance from focus or directrix to vertex on the axis of symmetry
\n" ); document.write( "4p=1
\n" ); document.write( "Equation: x^2=y-3
\n" ); document.write( "see graph below:
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C10%2C+-10%2C+10%2Cx%5E2%2B3%29+\"$ \n" ); document.write( "

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