document.write( "Question 617209: I think I need help to make sure I am doing this right. It says to solve:
\n" ); document.write( "2x^2 + 5 = 105
\n" ); document.write( "I subtracted 5 from each side for 2x^2 = 100
\n" ); document.write( "Divided by 2 on each side for x^2 = 50
\n" ); document.write( "I think I can use the principle of square roots here to arrive at x = square root (50)
\n" ); document.write( "I further break down the square root (50) to square root (25) X square root (2)
\n" ); document.write( "My final answer then becomes 5 square root (2)
\n" ); document.write( "Am I anywhere close?
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Algebra.Com's Answer #388207 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
I think I need help to make sure I am doing this right. It says to solve:
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document.write( "2x² + 5 = 105\r\n" );
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document.write( "    2x² = 100\r\n" );
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document.write( "     x² = 50\r\n" );
document.write( "            __\r\n" );
document.write( "      x = ±Ö50\r\n" );
document.write( "            ____ \r\n" );
document.write( "      x = ±Ö25·2\r\n" );
document.write( "            __  _\r\n" );
document.write( "      x = ±Ö25·Ö2\r\n" );
document.write( "             _\r\n" );
document.write( "      x = ±5Ö2\r\n" );
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document.write( "Your only error was forgetting the ± (positive or negative) when \r\n" );
document.write( "using the principle of square roots.\r\n" );
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document.write( "Edwin
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