document.write( "Question 617191:
\n" ); document.write( "(y+1)^2 = 12(x-1)\r
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Algebra.Com's Answer #388204 by Edwin McCravy(20059)\"\" \"About 
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(y + 1)² = 12(x - 1)\r
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\n" ); document.write( "We
\n" ); document.write( "(y - k)² = 4p(x - h)\r
\n" ); document.write( "\n" ); document.write( "has vertex (h,k). If p is positive it opens to the right.
\n" ); document.write( "If p is negative it opens to the left. its fccus is inside
\n" ); document.write( "the parabola on its axis on symmetry and |p| units from the
\n" ); document.write( "vertex.And the latus rectum or focal chord is |4p| units long
\n" ); document.write( "bisected by the focus.\r
\n" ); document.write( "\n" ); document.write( "Comparing your equation to that, we get\r
\n" ); document.write( "\n" ); document.write( "h=1, k= -1, 4p=12, so p=3\r
\n" ); document.write( "\n" ); document.write( "So the graph opens to the right because p is positive\r
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\n" ); document.write( "\n" ); document.write( "An the focus is a point inside the parabola |p| or 3 units
\n" ); document.write( "to the right of the vertex. The vertex is (1,-1), so the
\n" ); document.write( "focus is (4,-1) \r
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