document.write( "Question 7089: The numerator of a fraction is 10 less than the denominator. If 4 is added to each, the value of the resulting fraction is 3/5. Find the original fraction.
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document.write( "I've tried using multiples of 3/5 and subtracting 4 from the numerator and denominator hoping it will give me a solution where the numerator is 10 less than the denominator but I want a faster way of figuring this problemo ut just in case I ever get it on a test. \n" );
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Algebra.Com's Answer #3882 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! You could use this approach:\r \n" ); document.write( "\n" ); document.write( "Let d = the denominator.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "d = 21\r \n" ); document.write( "\n" ); document.write( "The original fraction is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \r \n" ); document.write( "\n" ); document.write( "Adding 4 to the numerator and to the denominator, we get: \n" ); document.write( " |