document.write( "Question 7089: The numerator of a fraction is 10 less than the denominator. If 4 is added to each, the value of the resulting fraction is 3/5. Find the original fraction.
\n" ); document.write( "I've tried using multiples of 3/5 and subtracting 4 from the numerator and denominator hoping it will give me a solution where the numerator is 10 less than the denominator but I want a faster way of figuring this problemo ut just in case I ever get it on a test.
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Algebra.Com's Answer #3882 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You could use this approach:\r
\n" ); document.write( "\n" ); document.write( "Let d = the denominator.\r
\n" ); document.write( "\n" ); document.write( "\"%28%28d-10%29%2B4%29%2F%28d%2B4%29+=+3%2F5\" Simplify then cross-multiply.\r
\n" ); document.write( "\n" ); document.write( "\"%28d-6%29%2F%28d%2B4%29+=+3%2F5\"
\n" ); document.write( "\"5%28d-6%29+=+3%28d%2B4%29\" Simplify and solve for d.
\n" ); document.write( "\"5d-30+=+3d%2B12\" Subtract 3d from both sides.
\n" ); document.write( "\"2d-30+=+12\" Add 30 to both sides.
\n" ); document.write( "\"2d+=+42\" Divide both sides by 2.
\n" ); document.write( "d = 21\r
\n" ); document.write( "\n" ); document.write( "The original fraction is:
\n" ); document.write( " \"%28d-10%29%2Fd\" or
\n" ); document.write( "\"%2821-10%29%2F21\"
\n" ); document.write( "\"11%2F21\" This is the original fraction.\r
\n" ); document.write( "\n" ); document.write( "Check: \r
\n" ); document.write( "\n" ); document.write( "Adding 4 to the numerator and to the denominator, we get:
\n" ); document.write( "\"%2811%2B4%29%2F%2821%2B4%29+=+15%2F25+=+3%2F5\"
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