document.write( "Question 616937: car A travels x km for every litre of petrol.while car B travels (x+5)km for every litre of petrol. if car A uses 4 litres of petrol more than car B in covering 400km, find the number of litres of petril used by car B for the journey. \n" ); document.write( "
Algebra.Com's Answer #388184 by ankor@dixie-net.com(22740)\"\" \"About 
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car A travels x km for every litre of petrol.while car B travels (x+5)km for every litre of petrol.
\n" ); document.write( "if car A uses 4 litres of petrol more than car B in covering 400km, find the number of litres of petril used by car B for the journey.
\n" ); document.write( ":
\n" ); document.write( "Car A's consumption - Car B consumption = 4 liters
\n" ); document.write( "\"400%2Fx\" - \"400%2F%28%28x%2B5%29%29\" = 4
\n" ); document.write( ":
\n" ); document.write( "multiply by x(x+5) to clear the denominators, results:
\n" ); document.write( "400(x+5) - 400x = 4x(x+5)
\n" ); document.write( "400x + 2000 - 400x = 4x^2 + 20x
\n" ); document.write( ":
\n" ); document.write( "Combine like terms, A quadratic equation
\n" ); document.write( "4x^2 + 20x - 2000 = 0
\n" ); document.write( ";
\n" ); document.write( "simplify, divide by 4
\n" ); document.write( "x^2 + 5x - 500 = 0
\n" ); document.write( ":
\n" ); document.write( "Factors to
\n" ); document.write( "(x+25)(x-20) = 0
\n" ); document.write( ":
\n" ); document.write( "the positive solution
\n" ); document.write( "x = 20 km/liter for Car A
\n" ); document.write( "then
\n" ); document.write( "25 km/liter for Car B
\n" ); document.write( "therefore
\n" ); document.write( "Car B: \"400%2F25\" = 16 liters for 400 km journey
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this solution by finding the consumption of Car A
\n" ); document.write( "400/20 = 20 liters, 4 liters more
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