document.write( "Question 57100: How do you write an expression for a polynomial of degree 3 with zeros, x= -3,1,-1 and f(2)=15? \n" ); document.write( "
Algebra.Com's Answer #38818 by stanbon(75887)\"\" \"About 
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How do you write an expression for a polynomial of degree 3 with zeros, x= -3,1,-1 and f(2)=15?
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\n" ); document.write( "Since you have those three zeroes you know the expression
\n" ); document.write( "has factors (x+3)(x-1)(x+1); but it may also have a constant
\n" ); document.write( "multiplier; so you write:
\n" ); document.write( "f(x)=a(x+3)(x-1)(x+1)
\n" ); document.write( "f(2)=a(5)(1)(3)=15
\n" ); document.write( "15a=15
\n" ); document.write( "a=1
\n" ); document.write( "So the equation is f(x)=1(x-3)(x-1)(x+1)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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