document.write( "Question 617047: For a particular sample of 77 scores on a psychology exam, the following results were obtained.
\n" ); document.write( "First quartile = 42 Third quartile = 69 Standard deviation = 10 Range = 54
\n" ); document.write( "Mean = 62 Median = 56 Mode = 83 Midrange = 66
\n" ); document.write( "Answer each of the following:
\n" ); document.write( "I. What score was earned by more students than any other score? Why?
\n" ); document.write( "II. What was the highest score earned on the exam?
\n" ); document.write( "III. What was the lowest score earned on the exam?
\n" ); document.write( "IV. According to Chebyshev's Theorem, how many students scored between 32 and 92?
\n" ); document.write( "V. Assume that the distribution is normal. Based on the Empirical Rule, how many students scored between 52 and 72?
\n" ); document.write( "Please show all of your work.
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Algebra.Com's Answer #388147 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "For a particular sample of 77 scores on a psychology exam, the following results were obtained.
\n" ); document.write( " First quartile = 42 Third quartile = 69 \"SD=+10\" \"Range+=+54\"
\n" ); document.write( " Mean = 62, Median = 56 \"Mode+=+83\" \"Midrange+=+highlight%2866%29\"
\n" ); document.write( "I. What score was earned by more students than any other score? by defn.\"Mode+=+83\"
\n" ); document.write( "II. What was the highest score earned on the exam? \"%28%28x-54%29%2Bx%29%2F2+=+66\", x =\"+93\"
\n" ); document.write( "III. What was the lowest score earned on the exam? \"93-54+=+highlight%2839%29\"
\n" ); document.write( " IV. According to Chebyshev's Theorem, how many students scored between 32 and 92? \"1+-+1%2F10%5E2+=+1-.01+=+.99\", \".99%2A77\" = 76.23 or 76
\n" ); document.write( " V. Assume that the distribution is normal. Based on the Empirical Rul...
\n" ); document.write( "how many students scored between 52 and 72? \".68+%2A+77+=+52.36\" OR 52
\n" ); document.write( "The empirical rule says that if you go 1 standard deviation out from the mean that you will capture 68 % of your data
\n" ); document.write( " Please show all of your work.
\n" ); document.write( " \n" ); document.write( "
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