document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=617001>Question 617001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate sqrt(3-3i). Give your answer in a+bi form. In polar form, use the angle 0<(theta)<2pi. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388080 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Calculate sqrt(3-3i). Give your answer in a+bi form. In polar form, use the angle 0<(theta)<2pi.<BR>\n" );
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document.write( "Polar form of 3-3i<BR>\n" );
document.write( "r = sqrt(3^2 + 3^2) = 3sqrt(2)<BR>\n" );
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document.write( "Note that (3,-3) is in the 4th Quadrant<BR>\n" );
document.write( "theta = tan^-1(-1) = (7/4)pi<BR>\n" );
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document.write( "General Form: <BR>\n" );
document.write( "3 - 3i = sqrt(18)(cos[(7/4)pi+2npi) + isin((7/4)pi+2npi)]<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "sqrt(3-3i) = ?<BR>\n" );
document.write( "If n = 0 you get: 18^(1/4)(cos(7/8)pi + isin(7/8)pi) = (18^1/4 , (7/8)pi)<BR>\n" );
document.write( "If n = 1 you get: 18^(1/4)(cos(15/8/pi + isin(15/8)pi)= (18^1/4 , (15/8)pi)<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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