document.write( "Question 57088: Helen Weller invested $15,000 in an account that pays 11% simple interest. How much additional money must be invested in an account that pays 14% simple interest so that the average return on the two investments amounts to 12%?
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Algebra.Com's Answer #38802 by stanbon(75887)\"\" \"About 
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Helen Weller invested $15,000 in an account that pays 11% simple interest. How much additional money must be invested in an account that pays 14% simple interest so that the average return on the two investments amounts to 12%?
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\n" ); document.write( "Interest #1: 15,000(0.11)= 1650
\n" ); document.write( "Interest #2: x(0.14)= 0.14x
\n" ); document.write( "EQUATIOH:
\n" ); document.write( "I think that word \"average\" can be misinterpreted on this problem.
\n" ); document.write( "Using it in the normal sense gives a negative value of \"x\".
\n" ); document.write( "Ignoring it you can get something meaningful, as follows:
\n" ); document.write( "(int#1+int#2) = 0.12(15000+x)
\n" ); document.write( "1650+0.14x = 1800+0.12x
\n" ); document.write( "0.02x=150
\n" ); document.write( "x=15000/2=$7500
\n" ); document.write( "That's the amount invested at 14% required so the total investment
\n" ); document.write( "will EQUAL 12% of all the money invested.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan h.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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