document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=616915>Question 616915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. You are given the coordinates of the vertex   (2,-2)  and of a point   (-9,3)   on a parabola. Find the coefficients for the equation of the parabola.<BR>\n" );
document.write( "Put in y=ax^2+bx+c form.\r<BR>\n" );
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document.write( "2.Given the functions <BR>\n" );
document.write( "f(x) = 5x2 &#8722; 4x + 2 <BR>\n" );
document.write( "g(x) = 3x + 6 <BR>\n" );
document.write( "Compute the following (you must simplify each polynomial as far as possible to receive full credit) Use the ^ (shift-6 on the keyboard) to enter a power. So to enter x2 + 3x + 1, you would type x^2 + 3x + 1. <BR>\n" );
document.write( "What is f(g(x))?<BR>\n" );
document.write( "What is g(f(x))? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388017 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  in vertex form ___ y = a(x - 2)^2 - 2<BR>\n" );
document.write( "___ substituting the given point (to find a) ___ 3 = a(-9 - 2)^2 - 2 ___ 5 = 121a ___ a = 5/121<BR>\n" );
document.write( "___ y = (5/121)(x - 2)^2 - 2 ___ y = (5/121)x^2 - (20/121)x - 238/121\r<BR>\n" );
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document.write( "2.  f(g(x)) = 5(3x+6)^2 - 4(3x+6) + 2 = 45x^2 + 180x + 180 - 12x - 24 + 2 = 45x^2 + 168x + 158\r<BR>\n" );
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document.write( "g(f(x)) = 3(5x^2 - 4x + 2) + 6 = 15x^2 - 12x + 6 + 6 = 15x^2 - 12x + 12 </SPAN>\n" );
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