document.write( "Question 616902: Given the following piecewise function:
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document.write( "f(x) = {(x+4 for x < -3) (-1 for -3 less than or equal to x <5)(2x for x > 5)}\r
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document.write( "a. Find the domain.
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document.write( "b. Find the range.
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document.write( "c. Find the intercepts.
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document.write( "d. Is f continous on its domain? If not, state where f discontinous.
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document.write( "e. Graph the function.\r
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document.write( "Please show steps for solving.\r
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document.write( "Thank you so very much! \n" );
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Algebra.Com's Answer #387967 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Given the following piecewise function: \n" ); document.write( "f(x) = {(x+4 for x < -3) \n" ); document.write( "(-1 for -3 less than or equal to x <5) \n" ); document.write( "(2x for x > 5)} \n" ); document.write( "--------------------------- \n" ); document.write( "a. Find the domain.All Real Numbers except x = 5 \n" ); document.write( "------------------------------- \n" ); document.write( "b. Find the range:::(-oo,1)U[10,+oo) \n" ); document.write( "-------------------------------------- \n" ); document.write( "c. Find the intercepts. \n" ); document.write( "x-intercept: (-4,0) \n" ); document.write( "y-intercept: (0.-1) \n" ); document.write( "--------------------------------------- \n" ); document.write( "d. Is f continous on its domain?:::No \n" ); document.write( "---------------------------------------- \n" ); document.write( " If not, state where f discontinous. \n" ); document.write( "Discontinuous at x = -3 and at x = 5 \n" ); document.write( "====================\r \n" ); document.write( "\n" ); document.write( "e. Graph the function. \n" ); document.write( "A piecewise function cannot be graphed on one set of axis on this site. \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================== \n" ); document.write( " |