document.write( "Question 616854: Barry is 8 years older than his sister. In 3 years, he will be twice as old as she will be then. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #387930 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Barry = b \n" ); document.write( "Present age of his sister = s\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Barry is 8 years older than his sister \n" ); document.write( "b=s+8..........(1)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 3 years \n" ); document.write( "Barry will be = b+3 \n" ); document.write( "His sister will be = s+3\r \n" ); document.write( "\n" ); document.write( "Then\r \n" ); document.write( "\n" ); document.write( "He will be twice as old as his sister will be\r \n" ); document.write( "\n" ); document.write( "b+3=2(s+3) \n" ); document.write( "b+3=2s+6 \n" ); document.write( "b=2s+6-3 \n" ); document.write( "b=2s+3.................(2)\r \n" ); document.write( "\n" ); document.write( "Substitute the value of b from (1) to (2)\r \n" ); document.write( "\n" ); document.write( "s+8=2s+3 \n" ); document.write( "s-2s=3-8 \n" ); document.write( "-s=-5 \n" ); document.write( "cancel out (-) \n" ); document.write( "s=5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the value of s in (1) \n" ); document.write( "b=s+8 \n" ); document.write( "b=5+8 \n" ); document.write( "b=13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Barry = b = 13 years old \n" ); document.write( "Present age of his sister = s = 5 years old \n" ); document.write( " \n" ); document.write( " |