document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=616809>Question 616809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need help solving for x:\r<BR>\n" );
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document.write( "2^(3x-2) = 3^(2x+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387915 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Need help solving for x: <BR>\n" );
document.write( "2^(3x-2) = 3^(2x+1)<BR>\n" );
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document.write( "Take the log of both sides:<BR>\n" );
document.write( "(3x-2)*log(2) = (2x+1)*log(3)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Get the x-terms together:<BR>\n" );
document.write( "3x*log(2) - (2x)*log(3) = log(3)-2log(2)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x[3log(2) - 2log(3)] = log(3)-2log(2)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = log[3/4]/log[8/9]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 2.4425<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
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