document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=616716>Question 616716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 2 angles and 1 side.  10 is on opposite and 10 is on adjacent.  On a right triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387901 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If it's a right triangle and two sides are equal then the two sides must be the legs and the triangle must be a 45-45-90 triangle.<br><BR>\n" );
document.write( "With a 45-45-90 triangle we do not really need Trig. If we remember the pattern for 45-45-90 triangles, we know that the hypotenuse is always <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%29 ALIGN=MIDDLE  ALT=\"sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > times the leg. So for this triangle the hypotenuse is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10sqrt%282%29 ALIGN=MIDDLE  ALT=\"10sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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