document.write( "Question 57084: THE LENGTH OF A RECTANGULAR GARDEN IS 8FT LESS THAN 3 TIMES IT'S WIDTH. IF THE PERIMETER OF THE GARDEN IS 48FT, FIND THE DIMENSIONS OF THE GARDEN.\r
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Algebra.Com's Answer #38788 by tutorcecilia(2152)\"\" \"About 
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P=2(length + width) [Use the formula for a perimeter]
\n" ); document.write( "P=48ft
\n" ); document.write( "Length= 3w-8
\n" ); document.write( "Width=w
\n" ); document.write( ".
\n" ); document.write( "48=2[(3w-8)+w]
\n" ); document.write( "48=2(3w-8+w)
\n" ); document.write( "48=2(4w-8)
\n" ); document.write( "48=8w-16
\n" ); document.write( "48+16=8w
\n" ); document.write( "64=8w
\n" ); document.write( "64/8=w
\n" ); document.write( "8ft=width
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\n" ); document.write( "Length:
\n" ); document.write( "l=3w-8
\n" ); document.write( "l=3(8)-8
\n" ); document.write( "l=24-8
\n" ); document.write( "Length = 16 ft
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\n" ); document.write( "Check by plugging the values of the perimeter, length and width into the formula for the perimeter of a rectangle.
\n" ); document.write( "48=2(16+8)
\n" ); document.write( "48=2(24)
\n" ); document.write( "48=48 [checks out]
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