document.write( "Question 616744: How do I solve this? Thank you!!\r
\n" ); document.write( "\n" ); document.write( "log[2](2x+15)-log[2](x)=3
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Algebra.Com's Answer #387871 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
applying \"log rules\":
\n" ); document.write( "log[2](2x+15)-log[2](x)=3
\n" ); document.write( "log[2](2x+15)/(x)=3
\n" ); document.write( "(2x+15)/(x)= 2^3
\n" ); document.write( "(2x+15)/x = 8
\n" ); document.write( "2x+15 = 8x
\n" ); document.write( "15 = 6x
\n" ); document.write( "15/6 = x
\n" ); document.write( "5/2 = x
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