document.write( "Question 616744: How do I solve this? Thank you!!\r
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document.write( "log[2](2x+15)-log[2](x)=3 \n" );
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Algebra.Com's Answer #387871 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! applying \"log rules\": \n" ); document.write( "log[2](2x+15)-log[2](x)=3 \n" ); document.write( "log[2](2x+15)/(x)=3 \n" ); document.write( "(2x+15)/(x)= 2^3 \n" ); document.write( "(2x+15)/x = 8 \n" ); document.write( "2x+15 = 8x \n" ); document.write( "15 = 6x \n" ); document.write( "15/6 = x \n" ); document.write( "5/2 = x \n" ); document.write( " \n" ); document.write( " |