document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=616698>Question 616698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the substitution method to solve<BR>\n" );
document.write( "3x-y=-10<BR>\n" );
document.write( "4x+4y=40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #387859 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=387859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply the first by 4 and then add the new equation to the second<BR>\n" );
document.write( "3x-y=-10<BR>\n" );
document.write( "12x-4y=-40<BR>\n" );
document.write( "4x+4y=40<BR>\n" );
document.write( "16x=0<BR>\n" );
document.write( "x=0<BR>\n" );
document.write( "y=10\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );